From Sevilla to Huelva.

Distance is 92.9 km

Google maps says it should take 1 hour (without traffic)

Calculate the speed...

92.9/1

speed is 92.9 km per hour.

- Not very much really.

Text

Did the car stop for petrol?

What was the fastest speed of the car?

What was the slowest speed of the car?

We know the car did not start at 92.9 km/h and then drive at a constant speed of 92.9 km/h until it reached Huelva then just stop.... but that seems to be what that information is telling us.

if the speed limit is the same for both, which can drive the fastest **legally**?

But which one gets **faster**, * faster*?

a =\frac{v - u}{t}

$a =\frac{v - u}{t}$

Acceleration is equal to the change in velocity divided by the time taken.

or

Acceleration = (final velocity - initial velocity)/time taken

a = \frac{v-u}{t}

$a = \frac{v-u}{t}$

at=v-u

$at=v-u$

v = u+at

$v = u+at$

(ii)

v_{average}=\frac{v+u}{2}

$v_{average}=\frac{v+u}{2}$

s=v_{average}. t

$s=v_{average}. t$

s=\frac{v+u}{2}.t

$s=\frac{v+u}{2}.t$

s=\frac{v+u}{2}.t

$s=\frac{v+u}{2}.t$

s=\frac{u+at+u}{2}.t

$s=\frac{u+at+u}{2}.t$

s=\frac{2u+at}{2}.t

$s=\frac{2u+at}{2}.t$

s=ut +\frac{at^2}{2}

$s=ut +\frac{at^2}{2}$

a = \frac{v-u}{t}

$a = \frac{v-u}{t}$

s = ut + \frac{1}{2}at^2

$s = ut + \frac{1}{2}at^2$

u

$u$

v

$v$

s

$s$

t

$t$

a

$a$