Volume: west window bays x east window bays x floors \[\text{Vol}(4,5,3) = 4\text{bays} \times 5\text{bays}\times 3\text{floors} = 60\text{rooms}.\]
Oops! Miss counted, but easy update: \[\text{Vol}(4,5+{\color{red}1},3)=\text{Vol}(4, 5, 3)+{\color{red}\text{Vol}(4,1,3)}=60+12=72\]
Need it in Cubic feet? Easy.
Vol(4,6,3) = 160 \(\text{ft}^4/\text{bay}^2~\text{floor}\) \(\times 4 \text{bays} \times 6\text{bays} \times 3 \text{floors}\)
\[\text{Area}\left(\begin{bmatrix} a\\ c\end{bmatrix}, \begin{bmatrix} b\\ d\end{bmatrix}\right) = (a+b)(c+d)-2bc-2\frac{1}{2}ac-2\frac{1}{2}bd=ad-bc= \begin{bmatrix} a & b\end{bmatrix}\begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix}\begin{bmatrix} c\\ d \end{bmatrix}\]
Area/Volume wrapped onto surfaces, measure inputs by proxy \[Jac(x,y)=\begin{bmatrix}\partial_x & \partial_y\end{bmatrix} \begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix}\begin{bmatrix} x\\ y\end{bmatrix}\]
Proportionate measures add strangely \[p_1\boxplus p_2=\frac{V_1}{V_3}p_1+\frac{V_2}{V_3}p_2\neq p_2\boxplus p_1\] E.g. adding gas pressure or supply/demand.
Scores from from VSChartz.com in 2021
Solution: compute the combination of rows specified by the recipe.
Galway --- Enfield
18:00 ---- 20:30
19:00 ---- 21:30
Galway --- Enfield
0.5 * 18:00 ---- 20:30
+ 0.5 * 19:00 ---- 21:30
-------------------------------------
18:30 ---- 21:00
Solution: Use the recipe
1/2 of bus 1 and 1/2 bus 2!
Consequence: You can change coordinates!
Or this...
Yes, even movies can be tensors...
How do you study something curved?
How do you study something curved?
With lines tangent to it!
Product Rule:
\[D(x*y)=D(x)*y+x*D(y)\]
We can do this on ANY tensor, and notice D is linear (exponent 1)
If we have products of different sizes or content, you independent coordinates \[H(x*y) = F(x)*y + x * G(y).\]
G
+
=
"Chisels" are selections of equations and constraints on the derivations, e.g.:\[C=\begin{bmatrix} 12 & 4 & -2 & 13\\ -1 & 0 & 1 & 5 \end{bmatrix}\] together with \[A=A^{\dagger}, B=Diag(B), C=D\]
They control what patterns can be discovered.
And it's solutions are a Lie algebra
If \(D_0(x*y)=5(x*y)\), \(D_1(x)=3x\) and \(D_2(y)=-2y\). [True for Eigenvectors]
Theorem. (Brooksbank-Kassabov-W.) Chisels detect cluster patterns in time \(O(n^{2})\).
Liu-Maglione-W.
Now \(O(n^{1+1/d})\) on average.
Theorem. Clusters you detect are essentially unique, because of the algebra.
"Random" Basis Change
Blind source separation
USDA Study "What We Eat in America" (add sugars data) .
(Experts: I don't know any better! Teach me!)
Watch magnetic changes under pulses that excite Hydrogen, Nitrogen, Carbonyl gives 3 axes.
Look for coordinates in wave space to identify what "tugs" on what, i.e. is the hydrogen attached to the nitrogen or the Carbon, etc.
Peaks in the wave frequency are the key.
FFT needs more measurements to find all 3 peaks.
Chiseling can retain statistically significant with data 1/2 to even 1/8 the data of the FFT.
Twice as fast means...
Half price.
More scans.
Finer features at same price.
FFT assumes frequency bins like keys on a piano.
Need more frequencies? Build a bigger piano.
Talks, Articles, and Books
PleaseDistribute.Org
Software:
TheTensor.Space (links to GitHub projects)
Tell me what I need to learn: James.Wilson@ColoState.Edu