2020 James B. Wilson
Colorado State University
\(+\) takes two values, \(x+y\) whereas \(-\) really ought to be two different symbols \(x-y\) for example verses \(-y\).
To avoid confusion in algebra \(x-y\) is always short-hand for \(x+(-y)\) therefore the difference is \(+\) expects 2 values, \(-\) only one.
Languages have alphabets + grammars. Math grammars are often very basic, e.g.:
allow this \(x+y\) but not this \(+xy\).
In algebra grammar all we need is the number of terms to combine in an operator.
E.g. 2 in the case of \(+,\times\), 1 in the case of - and ^-1.
The signature of an operator is the number of terms it requires to be formed in the language grammar.
Signature of \(+, \times\) is 2 because the proper use involves 2 terms, \(x+y\) or \(x\times y\)
Signature of \(-\) and ^-1 is 1 because the proper use involves 1 terms, \(-x\) or \(x^{-1}\).
Suppose we a new operator define \([,]\) by \([x,y]=xy-yx\). What is its signature?
2, because it needs both an x and a y.
Suppose we have a new operator \(\langle,\rangle\) defined by \(\langle x,y,z\rangle=x(yz)-(xy)z\). What is its signature?
3, because it needs x, y, and z.
For an entire system of algebra the signature is the list of arities of all the operators involved.
E.g. \(\mathbb{N}\) under \(+,\times,0,1\) has signature \(2,2,0,0\).
What is the signature of \(\mathbb{M}_2(\mathbb{R})\) under \(+,-,0,\times,1\)?
2,1,0,2,0
For different arities different conventions exist on how to write the operations for easy reading and detecting mistakes.