Suprema and Infima
Definition. Let \(S\) be a nonempty subset of \(\R\).
1. For each of the following determine whether the statement is true or false.
a) \(\{1-x^2 : x\in\R\}\) is bounded above.
b) \(\{x : |x+1|\leq 2\}\) is bounded.
c) \(\{x : |x-3|\geq 4\}\) is bounded.
d) If \(A\) is unbounded, then \(A\) is not bounded above.
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\(1\) is an upper bound since \(1-x^2\leq 1\) for all \(x\in\R\)
\(-4\) is a lower bound and \(2\) is an upper bound.
\(\{x : |x-3|\geq 4\}=(-\infty,-1]\cup[7,\infty)\)
\(A=(-\infty,1]\) is not bounded, since it is not bounded below, but \(1\) is an upper bound, so it is bounded above.
Definition. Let \(S\) be a nonempty subset of \(\R\).
1. If \(S\) is bounded above, then a number \(u\) is said to be a supremum (or least upper bound) of \(S\) if it satisfies the following conditions:
2. If \(S\) is bounded below, then a number \(w\) is said to be a infimum (or greatest lower bound) of \(S\) if it satisfies the following conditions:
If a set \(S\) has a supremum or an infimum, then they are denoted
\[\sup S\qquad\text{and}\qquad\inf S,\]
respectively.
Definition. Let \(S\) be a nonempty subset of \(\R\).
1. If \(S\) is bounded above, then a number \(u\) is said to be a supremum (or least upper bound) of \(S\) if it satisfies the following conditions:
It is very often that we will show the contrapositive of this is true, that is,
If \(u>v\), then \(v\) is not an upper bound of \(S\).
or, equivalently
If \(u>v\), then there is some \(s\in S\) such that \(s>v\).
1. For each of the following determine whether the statement is true or false.
a) If \(s=\sup A\), then \(s+1\) is an upper bound for \(A\).
b) If \(A\) has a supremum, then \(A\) has an infimum.
c) If \(s=\sup A\), then \(s+1\) is a supremum of \(A\).
d) If \(x\) and \(y\) are both lower bounds of \(A\) and \(x<y\), then \(y=\inf A\).
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\(s\) is an upper bound, that is, \(s\geq a\) for all \(a\in A\), so clearly \(s+1\geq a\) for all \(a\in A\).
\((-\infty,2)\) has a supremum, but it is not bounded below, so it cannot have an infimum
\(s+1\) is an upper bound, but \(s\) is also an upper bound and \(s<s+1\).
\(-50\) and \(-262.12\) are both lower bounds for \(\N\), but neither is an infimum.
Proposition. \(\sup(-\infty,2)=2\).
Proof. First, it is clear that \(2\) is an upper bound for \((-\infty,2)\).
Now, assume that \(u<2\). Note that
\[\frac{u+2}{2} <\frac{2+2}{2} = 2,\]
which shows that \(\frac{u+2}{2}\in(-\infty,2)\). Finally, we note that
\[\frac{u+2}{2}>\frac{u+u}{2} = u.\]
This shows that \(u\) is not an upper bound for \((-\infty,2)\). \(\Box\)
Read Section 2.3