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Write 2 functions, one that takes the a number in base 10 (decimal) and converts it to the string representation of that number in base 2 (binary), and one that converts back.
203 ""
101 "1"
50 "11"
25 "011"
12 "1011"
6 "01011"
3 "001011"
1 "1001011"
0 "11001011"
function decimalToBinary(num) {
if (!num) return "";
return decimalToBinary(Math.floor(num/2)) + num%2;
}
function decimalToBinary(num) {
var power = 2;
var binaryStr = '';
while(num) {
var remainder = num % power;
var digit = remainder ? 1 : 0;
binaryStr = digit + binaryStr;
num = num - remainder;
power *= 2;
}
return binaryStr;
}
function binaryToDecimal(numStr) {
if (!numStr.length) return 0;
return binaryToDecimal(numStr.slice(0, -1))*2
+ Number(numStr[numStr.length-1]);
}
OR
function binaryToDecimal (numStr) {
var sum = 0;
var reversedStr = numStr.split('').reverse();
for (var i = 0; i < reversedStr.length; i++) {
sum += Math.pow(2, i) * reversedStr[i];
}
return sum;
}