Goal: Find consequences with minimal number of clues.
Clues?
Idea:
How can we find consequences?
\( \exists clues :: \mathcal{Kb} : \exists reif : \exists prop, subj, val, dt: dt \neq U \land \forall extensions :: \mathcal{Kb} : Theory(PK, clues, reif, extensions) \Rightarrow extensions(prop,subj,val, dt)\)
| Penne | Farfall | spirelli | Arrabi | Bologn | Carbon | ||
|---|---|---|---|---|---|---|---|
| Andrea | |||||||
| Bart | |||||||
| Casper |
| arrabi | |||
| Bologn | |||
| Carbon |
My instance
| Penne | Farfall | spirelli | Arrabi | Bologn | Carbon | ||
|---|---|---|---|---|---|---|---|
| Andrea | X | - | - | - | - | X | |
| Bart | - | X | - | X | - | - | |
| Casper | - | - | X | - | X | - |
| arrabi | - | X | - |
| Bologn | - | - | X |
| Carbon | X | - | - |
My instance
Transitivity