Action Principle

Revision 2

We know ... 

n_1 \sin{\theta_1} = n_2 \sin{\theta_2}
n = \frac{c}{v}
\frac{c}{v_1} \sin{\theta_1} = \frac{c}{v_2} \sin{\theta_2}
\frac{\sin{\theta_1}}{v_1} = \frac{\sin{\theta_2}}{v_2}

Say

v \propto \sqrt{2gy}
\frac{\sin{\theta_1}}{\sqrt{y_1}} = \frac{\sin{\theta_2}}{\sqrt{y_2}}
\frac{\sin{\theta_1}}{\sqrt{y_1}} = \frac{\sin{\theta_2}}{\sqrt{y_2}}
\frac{\sin{\theta_1}}{f(y_1)} = \frac{\sin{\theta_2}}{f(y_2)}
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