Chapter I
\text{Chapter I}
Chapter I
\text{Chapter I}
Chapter I
\text{Chapter I}
Chapter I
\text{Chapter I}
Express speed of sound, 330 m/s in miles/h
\text{Express speed of sound, }330 \mathrm{~m} / \mathrm{s}\text{ in miles}/ \mathrm{h} \\
(1 mile=1609 m)
(1 \text{ mile}=1609 \mathrm{~m})
Problem 1
\text{Problem 1}
Express speed of sound, 330 m/s in miles/h
\text{Express speed of sound, }330 \mathrm{~m} / \mathrm{s}\text{ in miles}/ \mathrm{h} \\
(1 mile=1609 m)
(1 \text{ mile}=1609 \mathrm{~m})
Answer C
\text{Answer C}
Problem 1
\text{Problem 1}
(1 nano =10−9)
1 shake=10−8 seconds.
Find out how many nano seconds (ns) are there in 1 shake.
Problem 2
\text{Problem 2}
(1 nano =10−9)
1 shake=10−8 seconds.
Find out how many nano seconds (ns) are there in 1 shake.
Problem 2
\text{Problem 2}
Answer E
\text{Answer E}
How many molecules of water are there in a cup containing 250 cm3 of water?
Molecular mass of H2O=18 g/mole
Density of water =1.0 g/cm3
Avogadro s number =6.02×1023molecules/mole
A) 6.0×1023
B) 8.4×1024
C) 1.9×1026
D) 3.7×1028
E) 2.5×103
Problem 3
\text{Problem 3}
How many molecules of water are there in a cup containing 250 cm3 of water?
Molecular mass of H2O=18 g/mole
Density of water =1.0 g/cm3
Avogadro s number =6.02×1023molecules/mole
A) 6.0×1023
B) 8.4×1024
C) 1.9×1026
D) 3.7×1028
E) 2.5×103
Problem 3
\text{Problem 3}
Answer B
\text{Answer B }
Problem 4
\text{Problem 4}
Problem 4
\text{Problem 4}
Answer A
\text{Answer A}
Problem 5
\text{Problem 5}
Problem 5
\text{Problem 5}
Answer D
\text{Answer D}
[v]=[A][t]2 and [v]=[A][B][t]
\displaystyle [v]=[A][t]^2\text{ and }[v]=\frac{[B]}{[A]}[t]
LT−1=[A]T2 and [v]=[A][B]T
\displaystyle LT^{-1}=[A]T^2\text{ and }[v]=\frac{[B]}{[A]}T
In a sum or an equality, all the terms have the same dimension
\text{In a sum or an equality, all the terms have the same dimension}
LT−1=[A]T2
\displaystyle LT^{-1}=[A]T^2
LT−1=[A][B]T
\displaystyle LT^{-1}=\frac{[B]}{[A]}T
and
\text{ and }
⇒
\Rightarrow
LT−3=[A]
\displaystyle LT^{-3}=[A]
⇒
\Rightarrow
[A]LT−2=[B]
\displaystyle [A]LT^{-2}=[B]
L2T−5=[B]
\displaystyle L^2T^{-5}=[B]
⇒
\Rightarrow
The transverse displacement of an oscillating string is given by y=ymcos(ωt+ϕ)
\text{The transverse displacement of an oscillating string is given by } y=y_m \cos(\omega t+\phi)
where y, is in cm and t in ms.
\text{where }y,\text{ is in cm and }t \text{ in ms}.
What is the dimension of ω?
\text{What is the dimension of }\omega?
Problem 7
\text{Problem 7}
The transverse displacement of an oscillating string is given by y=ymcos(ωt+ϕ)
\text{The transverse displacement of an oscillating string is given by } y=y_m \cos(\omega t+\phi)
where y, is in cm and t in ms.
\text{where }y,\text{ is in cm and }t \text{ in ms}.
What is the dimension of ω?
\text{What is the dimension of }\omega?
The term inside a trigonometric function has no dimension. Therefore, we can write:
\text{The term inside a trigonometric function has no dimension. Therefore, we can write:}
[ω][t]=1⇒[ω]=T−1
[\omega][t]=1\Rightarrow [\omega]=T^{-1}
Problem 7
\text{Problem 7}
Problem 8
\text{Problem 8}
Problem 8
\text{Problem 8}
Answer C
\text{Answer C}
Problem 9
\text{Problem 9}
Problem 9
\text{Problem 9}
Answer E
\text{Answer E}
Problem 10
\text{Problem 10}
Answer B
\text{Answer B}
Problem 11
\text{Problem 11}
Problem 11
\text{Problem 11}
Answer D
\text{Answer D}
C h a p t e r I \text{Chapter I} C h a p t e r I \text{Chapter I} C h a p t e r I \text{Chapter I} C h a p t e r I \text{Chapter I}