Obfuscated Fizzbuzz
David Watson
david@davidwatson.org
Slides
https://github.com/davidthewatson/obfuscated_fizzbuzz
Slides
https://github.com/davidthewatson/obfuscated_fizzbuzz
Original Source and Analysis
https://github.com/davidthewatson/fizzbuzz
Originally delivered as a lightning talk to Pittsburgh Python
What is fizzbuzz?
A book
of Spoken Numeracy Games
by Janet Rees
Co-opted
into an interview question
For the numbers from 1 to 100
If the number is evenly divisible by 3 print fizz
If the number is evenly divisible by 5 print buzz
If the number is evenly divisible by 3 and 5 print fizzbuzz
Else print the number
by Imran Ghory
Made popular
by Jeff Atwood's
Coding Horror
The continuum
from obfuscation to clarity
Obfuscated FizzBuzz
Lambdas, closures, nested generator expressions
print(*((lambda x=x: ''.join(chr(c) for c in (102, 105)) + (2 * chr(122)) + ''.join(chr(c) for c in (98, 117)) + (2 * chr(122)) + '\n' if x % (30 >> 1) == 0 else ''.join(chr(c) for c in (102, 105)) + (2 * chr(122)) + '\n' if x % (6 >> 1) == 0 else ''.join(chr(c) for c in (98, 117)) + (2 * chr(122)) + '\n' if x % (10 >> 1) == 0 else str(x) + '\n')() for x in range(1, 101)))
Only a crazed lisp programmer could love
Byzantine FizzBuzz
Less than ten lines of python
from itertools import chain
all = list(range(1, 101))
divisible_by_3 = dict((x, 'Fizz') for x in filter(lambda x: x % 3 == 0, all))
divisible_by_5 = dict((x, 'Buzz') for x in filter(lambda x: x % 5 == 0, all))
divisible_by_3_and_5 = dict((x, 'FizzBuzz') for x in
filter(lambda x: x % 3 == 0 and x % 5 == 0, all))
remainder = dict((x, x) for x in [x for x in all
if not x in divisible_by_3
and not x in divisible_by_5
and not x in divisible_by_3_and_5])
all_dict = dict(chain(divisible_by_3.items(),
divisible_by_5.items(),
divisible_by_3_and_5.items(),
remainder.items()))
for x in all:
print(all_dict[x])
Only a crazed discrete math professor could love
Canonical Fizzbuzz
The simplest thing that could possibly work
for i in range(1, 101):
if i % 15 == 0:
print('FizzBuzz')
elif i % 3 == 0:
print('Fizz')
elif i % 5 == 0:
print('Buzz')
else:
print(i)
Is also susceptible to rote memorization
All three solutions
produce expected output and perform similarly
1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz Fizz 22 23 Fizz Buzz 26 Fizz 28 29 FizzBuzz 31 32 Fizz 34 Buzz Fizz 37 38 Fizz Buzz 41 Fizz 43 44 FizzBuzz 46 47 Fizz 49 Buzz Fizz 52 53 Fizz Buzz 56 Fizz 58 59 FizzBuzz 61 62 Fizz 64 Buzz Fizz 67 68 Fizz Buzz 71 Fizz 73 74 FizzBuzz 76 77 Fizz 79 Buzz Fizz 82 83 Fizz Buzz 86 Fizz 88 89 FizzBuzz 91 92 Fizz 94 Buzz Fizz 97 98 Fizz Buzz
But only the last is understandable and derivable
TRIVIAL PROBLEMS DESERVE CANONICAL SOLUTIONS.
Obfuscated Fizzbuzz
By davidthewatson
Obfuscated Fizzbuzz
Exploring the continuum from obfuscation to clarity using fizzbuzz and python.
- 1,830