
date of defense and thesis submission
\text{date of defense and thesis submission}
Jury validated version
\text{Jury validated version}
version modified by author
\text{version modified by author}



Nice and easy 2stand
\text{Nice and easy $\frac{\text{stand}}{2}$}

500 K
\text{500 K}
400 K
\text{400 K}
∣W∣
|W|
∣QH∣=540J
|Q_H|=540\hspace{1mm} J
∣QL∣=400J
|Q_L|=400\hspace{1mm} J
∣QH∣=500J
|Q_H|=500\hspace{1mm} J
∣W∣=120J
|W|=120\hspace{1mm}J
∣W∣
|W|
∣QH∣
|Q_H|
∣QL∣
|Q_L|
∣QL∣
|Q_L|
Engine 1
\text{Engine } 1
Engine 2
\text{Engine } 2
Engine 3
\text{Engine } 3

+
+
−
-
C3
C_3
C2=12μF
C_2=12\hspace{1mm}\mu F
C1=4.0μF
C_1=4.0\hspace{1mm}\mu F
C3=2.0μF
C_3=2.0 \hspace{1mm}\mu F
C1
C_1
C2
C_2
Cf=κCi=6.5×13.5=87.75pF Charge is conserved: Q=CiVi=13.5×12.5=168.75pCUf=2CfQ2=2×87.75×10−12(168.75×10−12)2=1.62×10−10J=162×10−12J=162pJ
\begin{aligned}
&\mathrm{C}_{\mathrm{f}}=\kappa \mathrm{C}_{\mathrm{i}}=6.5 \times 13.5=87.75 \mathrm{pF}\\
&\text { Charge is conserved: } Q=C_i V_i=13.5 \times 12.5=168.75 p C\\
&U_f=\frac{Q^2}{2 C_{\mathrm{f}}}=\frac{\left(168.75 \times 10^{-12}\right)^2}{2 \times 87.75 \times 10^{-12}}=1.62 \times 10^{-10} J=162 \times 10^{-12} J=162 \mathrm{pJ}
\end{aligned}
d a t e o f d e f e n s e a n d t h e s i s s u b m i s s i o n \text{date of defense and thesis submission} J u r y v a l i d a t e d v e r s i o n \text{Jury validated version} v e r s i o n m o d i f i e d b y a u t h o r \text{version modified by author}
Quiz chapter 23
By smstry
Quiz chapter 23
- 110