Momentum and Energy
M. Rocha
Physics 10
Elephant has more inertia than skaterat
m < M
Moving
Not Moving
Elephant has no momentum at rest
What about momentum?
Moving
Moving
Elephant got momentum!
Momentum is inertia in motion
Momentum=mass×velocity
\mathrm{Momentum} = \mathrm{mass} \times \mathrm{velocity}
p=mv
p = mv
A container ship has lots of momentum even when moving slow because it has a lot of mass
Checkpoint
Which has more momentum, a 3000 kg elephant moving at 1 km/h or a 0.3 kg mice moving at 10000 km/h?
Both have the same momentum of 3000 kg km/h
p=mv
p = mv
Impulse is change in momentum
Impulse=change in momentum
\mathrm{Impulse} = \mathrm{change \ in \ momentum}
Force×time=Δ(mv)
\mathrm{Force} \times \mathrm{time} = \Delta(mv)
Ft=Δ(mv)
Ft = \Delta(mv)
Impulse-momentum relationship
Impulse=Force×time
\mathrm{Impulse} = \mathrm{Force} \times \mathrm{time}
Ft=Δ(mv)
Ft = \Delta(mv)
Impulse-Momentum Relationship
Ft=Δ(mv)
Ft = \Delta(mv)
Large t, small F
Large F, small t
Impulse-Momentum Relationship
Dynamic ropes reduce the force by increasing the time to stop
Checkpoint
If a dynamic rope is able to increase the duration of a rock climber's fall by four times, how much would the force of impact change?
The force is reduced by four
Ft=Δ(mv)
Ft = \Delta(mv)
Bouncing increases impulse
Change in momentum of teddy bear vs. bouncing ball
Bouncing increases impulse
Conservation of momentum
In the absence of an external force, the momentum of a system remains unchanged
pcannon+pball=0
p_\mathrm{cannon} + p_\mathrm{ball} = 0
pcannon+pball=0
p_\mathrm{cannon} + p_\mathrm{ball} = 0
Initial momentum
Final momentum
=
=
Conservation of momentum
m(v)
m(v)
Initial momentum
Final momentum
Big Fish
Small Fish
5m(5v)
5m(\frac{v}{5})
4m(0)
4m(0)
Small Fish
Big Fish
0
0
+
+
+
+
=
=
?
Elastic Collisions
Inelastic Collisions
Energy and momentum are conserved
Momentum is conserved but energy is not
Momentum is always conserved regardless of the type of collision!
vs.
Objects rebound without lasting deformation or heat generation
Objects get tangled and/or generate heat
Collisions
Net momentum before collision = Net momentum after collision
Checkpoint
What is the velocity of the blue truck after the collision?
5 m/s
∑pbefore=∑pafter
\sum{p_\mathrm{before}} = \sum{p_\mathrm{after}}
Checkpoint
What is the velocity of grandma and grandson after the collision?
4 m/s
∑pbefore=∑pafter
\sum{p_\mathrm{before}} = \sum{p_\mathrm{after}}
Momentum IS A VECTOR!
The sum of the momenta vectors is the same before and after the collision/explosion
Energy
Energy may be the most familiar concept in science, yet it is one of the most difficult to define
Here we are going to focus on Mechanical Energy: Work, Kinetic Energy and Potential Energy
Work
Work is proportional to force and distance
Work
Work is proportional to force and distance
Work=Force×distance
\mathrm{Work} = \mathrm{Force} \times \mathrm{distance}
W=Fd
W = F d
Work
W=Fd
W = F d
The wall is not moving, so d = 0 and thus W = 0
Is he doing work on the wall?
Work
W = Fx d
Fx
Fy
Fy is not doing any work since the block doesn't move on the y direction
Is the Earth doing work on the Moon?
No because the force is not in the direction of motion
Checkpoint 1
Units of Work
W=Fd
W = F d
Work Units=Force Units×Distance Units
\mathrm{Work \ Units} = \mathrm{Force \ Units} \times \mathrm{Distance \ Units}
=N×m=kgs2m×m=kgs2m2=1 Joule
= N \times m = kg \frac{m}{s^2} \times m = kg \frac{m^2}{s^2} = 1 \ \mathrm{Joule}
Work has units of Energy
Work is Energy in transfer!
Checkpoint 2
How much work is needed to lift a bag of groceries that weights 300 N to a height of 2 m?
600 Joules
W=Fd
W = F d
Power
Power=Time intervalWork done=tW
\mathrm{Power} = \frac{\mathrm{Work \ done}}{\mathrm{Time \ interval}} = \frac{W}{t}
Power Units=Time UnitsWork Units=sJ=watt
\mathrm{Power \ Units} = \frac{\mathrm{Work \ Units}}{\mathrm{Time \ Units}} = \frac{J}{s} = \mathrm{watt}
1 horsepower = 746 watts
Power is the rate at which work is done.
Power is the rate at which energy is transferred!
Checkpoint 3
To lift a bag of groceries up the stairs in half the time you need ________ as much power?
Twice
Power=tW
\mathrm{Power} = \frac{W}{t}
With twice as much power you can do either the same work in half the time or twice as much work in the same time
Work=ΔE
\mathrm{Work} = \Delta{\mathrm{E}}
Work-Energy theorem
The Floor is doing work on the bicycle, thus the bicycle's Energy must change (it decreases as it stops moving).
The Energy due to the bicycle's motion turns into heat
Kinetic Energy
The energy due to an object moving
Kinetic Energy
KE=21mass×velocity2
\mathrm{KE} = \frac{1}{2} \mathrm{mass} \times \mathrm{velocity^2}
KE=21mv2
\mathrm{KE} = \frac{1}{2} m v^2
Potential Energy
The energy that is stored and held in readiness due to the position of an object (the arrow in this case)
Potential Energy -> Kinetic Energy
The Potential Energy of the arrow is converted to Kinetic Energy
Potential Energy
The energy that is stored and held in readiness due to the position of an object (the car in this case)
Work --> Potential Energy
Potential Energy --> Kinetic Energy
Gravitational Potential Energy
The potential energy of the ball is independent of how the ball got to its position, in all cases
PE = mg (3 meters)
Gravitational Potential Energy = weight x height
PE=mg h
\mathrm{PE} = mg \ h
h = 3 meters
The energy associated to the gravitational force and the work it does on objects
Checkpoint 4
Ignoring friction, which path requires the most work? (hint: remember that work is transfer of energy)
They all require the same amount of work =
PE=mg h
\mathrm{PE} = mg \ h
Mechanical Energy
E=21mv2+mgh
E = \frac{1}{2} m v^2 + mg h
Mechanical Energy=Kinetic Energy+Potential Energy
\mathrm{Mechanical \ Energy} = \mathrm{Kinetic \ Energy} + \mathrm{Potential \ Energy}
E=KE+PE
E = \mathrm{KE} + \mathrm{PE}
When the Potential Energy is gravitational:
Conservation of Energy
Energy cannot be created or destroyed: it may be transformed from one form into another, but the total amount of energy never changes
Conservation of Energy
E=21mv2+mgh=Constant
E = \frac{1}{2} m v^2 + mg h = \mathrm{Constant}
E=KE+PE=Constant
E = \mathrm{KE} + \mathrm{PE} = \mathrm{Constant}
When the Potential Energy is gravitational
In the absence of external work the mechanical energy of a systems remains constant
Conservation of Energy
The End
Momentum and Energy M. Rocha Physics 10
Momentum and Energy (Physics 10)
By Miguel Rocha
Momentum and Energy (Physics 10)
Physics 1 - Week 3 - Chapters 6 and 7
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