Loops
Muhammad Magdi
Increment Operator
x = x + 1;
This statement assigns to `x` the value of `x` + 1:
gets the old value of `x`, then adds 1 to it, then stores the new value in `x` again.
This operation can also be done using the increment operator.
x++;
URI 1060 - Positive Numbers
[Problem Summary]
- Read 6 decimal numbers.
- Print an integer number indicating how many positive numbers were there in the input.
- Follow this number by the word " valores positivos".
URI 1060 - Positive Numbers
[Solution #1]
#include <iostream>
using namespace std;
int main() {
double a, b, c, d, e, f;
cin >> a >> b >> c >> d >> e >> f;
int counter = 0;
if (a > 0) {
counter++;
}
if (b > 0) {
counter++;
}
if (c > 0) {
counter++;
}
if (d > 0) {
counter++;
}
if (e > 0) {
counter++;
}
if (f > 0) {
counter++;
}
cout << counter << " valores positivos" << endl;
return 0;
}URI 1060 - Positive Numbers
[Notes]
- For each input number we:
- Declared a variable "double a".
- Took it as input "using cin".
- Checked if it's positive "using if".
- What if there were more than 6 Numbers as input?
- What if they were 10 numbers? 100 Numbers? Millions of numbers?...
For Loops
for ( INITIALIZATION; CONDITION; ASSIGNMENT ) {
BODY
}
INITIALIZATION: What to do before starting the loop?
CONDITION: What is the condition to continue looping?
ASSIGNMENT: What to do after each iteration?
URI 1060 - Positive Numbers
[Solution #2]
#include <iostream>
using namespace std;
int main() {
int counter = 0;
for (int i = 1; i <= 6; i++) {
double x;
cin >> x;
if (x > 0) {
counter++;
}
}
cout << counter << " valores positivos" << endl;
return 0;
}
URI 1060 - Positive Numbers
[Notes]
- The Lines from 8 to 12 will be repeated 6 times.
- Each repetition is called iteration.
Assignment
Thanks
Content
- Increment Operator
- URI 1060 - Positive Numbers
- For Loops
- URI 1060 - Positive Numbers Again
Loops1
By Muhammad Magdi
Loops1
- 169
