Motivating Question

Factoring Quadratics

(Leading Coefficient=1)

 

\pi \cdot \pi

\((x+3)(x+4)\)

Multiply \((x+3)(x+4)\)

\pi \cdot \pi

\((x+3)(x+4)\)

=\(x(x+4)+3(x+4)\)

Multiply \((x+3)(x+4)\)

\pi \cdot \pi

\((x+3)(x+4)\)

=\(x(x+4)+3(x+4)\)

=\(x^2+4x+3x+12\)

Multiply \((x+3)(x+4)\)

\pi \cdot \pi

\((x+3)(x+4)\)

=\(x(x+4)+3(x+4)\)

=\(x^2+4x+3x+12\)

=\(x^2+7x+12\)

Multiply \((x+3)(x+4)\)

\pi \cdot \pi

...you were asked to find the two polynomials that could be multiplied to give \(x^2+7x+12\).

 

What if...

\pi \cdot \pi

Factoring Quadratics with a Leading Coefficient of 1 MQ

By Anurag Katyal

Factoring Quadratics with a Leading Coefficient of 1 MQ

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