Factoring Quadratics
(Leading Coefficient=1)
(x+3)(x+4)(x+3)(x+4)(x+3)(x+4)
Multiply (x+3)(x+4)(x+3)(x+4)(x+3)(x+4)
=x(x+4)+3(x+4)x(x+4)+3(x+4)x(x+4)+3(x+4)
=x2+4x+3x+12x^2+4x+3x+12x2+4x+3x+12
=x2+7x+12x^2+7x+12x2+7x+12
...you were asked to find the two polynomials that could be multiplied to give x2+7x+12x^2+7x+12x2+7x+12.
What if...
By Anurag Katyal
