Dividing by zero

2 + 2 = 4 \\ 4 -1 = 3
3 . 5 = 3 + 3 + 3 + 3 + 3 \\ 5 . 3 = 5 + 5 + 5
\frac{15}{5} = 3 \\ 15 -5 -5 -5 = 0
\frac{1}{0} = 1 - \underbrace{ 0 - 0 - 0 - 0 - 0 - 0 - ...}_{ \infty ?} \newline

Examples

\frac{1}{0} = \infty ?

First approach

\frac{1}{1} = 1 \\ \frac{1}{0.1} = 10 \\ \frac{1}{0.01} = 100 \\ \frac{1}{0.001} = 1000 \\ \frac{1}{0.0001} = 10000 \\ . \\ . \\ . \\

Examples

Second approach

\frac{1}{0} = \infty ?
\frac{3}{1} = 3 \\ \frac{3}{0.1} = 30 \\ \frac{3}{0.01} = 300 \\ \frac{3}{0.001} = 3000 \\ \frac{3}{0.0001} = 30000 \\ . \\ . \\ . \\

Examples

Second approach

\frac{3}{0} = \infty ?

Weird

\frac{1}{0} = \infty = \frac{3}{0} \\ \frac{1}{0} = \frac{3}{0} \\ 1 = 3 ??? . \\ . \\ 1 \neq 3

This is fundamentally wrong !!!

Undefined

\frac{1}{0} = undefined

Another approach to zero

\frac{1}{-1} = -1 \\ \frac{1}{-0.1} = -10 \\ \frac{1}{-0.01} = -100 \\ \frac{1}{-0.001} = -1000 \\ \frac{1}{-0.0001} = -10000 \\ . \\ . \\ . \\
\frac{1}{0} = - \infty

There is not number you can pick that make sense !!! Therefore, Undefinable

\lim_{x\to0} \frac{1}{x} = \text{does not exist}
\lim_{x^{+}\to0} \frac{1}{x} = \infty
\lim_{x^{-}\to0} \frac{1}{x} = -\infty

Dividing by zero

By Michal Danco

Dividing by zero

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