Atomic models
The evolution of atomic models at the beginning of the 20th century
Atomic models
Overview
Evidence in 1900 indicated that the atom was not a fundamental unit:
- There seemed to be too many kinds of atoms, each belonging to a distinct chemical element.
- Atoms and electromagnetic phenomena were intimately related (magnetic materials; insulators vs. conductors; different emission spectra).
- Elements combine with some elements but not with others, a characteristic that hinted at an internal atomic structure (valence).
- The discoveries of radioactivity, x-rays, and the electron (all seemed to involve atoms breaking apart in some way).
overview
We will follow the progression of atomic modeling in the early 20th century
Atomic models
just a bit more about atomic spectra
Balmer series (1885)
\lambda = 364.6 \text{nm} \left(\frac{k^2}{k^2-4}\right)
Empirically, Balmer found an expression for the pattern of wavelengths in the Hydrogen spectrum
using a diffraction grating (fancy prism) that we are able to separate a beam of light into its spectral components
and that the emission spectra from different elements showed different components
Recall
\text{where} \quad k=3,4,5, ...
\text{e.g.}\quad k=3 \implies\lambda = 364.6 \text{nm} \left(\frac{3^2}{3^2-4}\right)=656.3\text{nm}
Atomic models
just a bit more about atomic spectra
Rydberg and Ritz (1890)
\frac{1}{\lambda} = \frac{1}{364.6 \text{nm}} \left(\frac{k^2-4}{k^2}\right)=\frac{4}{364.6 \text{nm}} \left(\frac{1}{2^2}-\frac{1}{k^2}\right)
Rydberg and Ritz recognized that Balmer's result can be expressed as:
\frac{1}{\lambda} = R_H\left(\frac{1}{n^2}-\frac{1}{k^2}\right)
Which generalizes to
Which generalizes to
\text{where} \quad R_H=1.0968 \times10^7 m^{-1}
Atomic models
Early atomic models
Thomson's model
Atomic models
Early atomic models
Thomson's model
- Electrons (discovered in 1897) carry negative charge and are very light compared to atomic masses.
- To achieve net charge neutrality, atoms must also contain positive charge.
- The majority of the atomic mass is distributed over a large volume.
- Electrons are fairly stationary within the atom, oscillating in place in accordance with temperature. Oscillations of electrons give rise to EM radiation.
- This model can explain the variety of atoms.
Features of Thomson's model
Atomic models
Early atomic models
Thomson's model meets the real world.
Rutherford, Geiger, and Marsden used radioactive emission to study the structure of matter.
According to the Thomson model, the scattering angle of an alpha-particle from a gold atom would be very small.
However, experimental observations (in1909) of large-angle scattering were in direct disagreement with the predictions of Thomson's model.
Atomic models
Early atomic models
Rutherford's model
This suggested to Rutherford, that the positive charge must be concentrated in a small nucleus! Hence, the birth of the planetary model of the atom!
Atomic models
Early atomic models
Rutherford's scattering analysis
- The nucleus is assumed to be a point charge.
- The alpha particle is assumed to be a point charge, approaching in a path, which if not deflected, would pass at a distance from the nucleus known as the impact parameter.
- The alpha particle and the nucleus interact with a Coulomb force, that ends up deflecting the alpha particle by some angle relative to its original path.
The geometry of Rutherford's scattering.
Atomic models
Early atomic models
Rutherford's scattering analysis
The physics of Rutherford's scattering.
- The change in momentum manifests as a change of the direction of motion of the alpha particle.
- The Coulomb force is inversely proportional to the square of the ever-varying distance between the alpha particle and the nucleus.
\vec{F} = \frac{1}{4\pi\epsilon_0}\ \frac{(Z_1 e) (Z_2 e)}{r^2}\ \hat{r}
\Delta \vec{p} =\int \vec F dt
- The change in the alpha particle's momentum is equivalent to the impulse exerted on it by the nucleus:
Atomic models
Early atomic models
Rutherford's scattering analysis
In this model, the scattering angle is highly dependent on the impact parameter, and can indeed be quite large for small impact parameters.
b = \frac{Z_1 Z_2 e^2}{8\pi\epsilon_0 K} \cot{ \frac{\theta}{2}}
Atomic models
Early atomic models
Rutherford's scattering analysis
Rutherford's model was successful in explaining the results of the scattering experiments.
Today, we know a lot more about the atomic nucleus; and one of the enduring ideas is that the nucleus contains most of the atomic mass in a volume that is a very small fraction of the size of an atom.
The spatial extension of a typical nucleus is ~ fm
The comparative spatial extension of the atomic nucleus to the spatial extension of the electronic cloud in an atom is of the same order as the ratio of the size of your thumb compared to the size of UCF campus.
Atomic models
Early atomic models
The classical planetary model
In the planetary model: electrons carrying the negative charge, orbit the nucleus where the positive charge is concentrated, and the system is bound by the electrostatic potential.
Atomic models
Early atomic models
The classical planetary model
Atomic models
Early atomic models
The classical planetary model
Let's examine the Hydrogen atom: 1 proton + 1 electron
What is the total energy of the atom
(in the proton's frame)?
Atomic models
Early atomic models
The classical planetary model
Let's examine the Hydrogen atom: 1 proton + 1 electron
What is the total energy of the atom
(in the proton's frame)?
Electron's Kinetic Energy
K=\tfrac{1}{2}m_ev^2
=\tfrac{1}{2}m_e\frac{v^2}{r}r
=\frac{k e^2}{2r}
=\tfrac{1}{2}m_e a_c r
=\tfrac{1}{2}F_c r
=\tfrac{1}{2} \left( k \frac{|e \ (-e)|}{r^2}\right)r
Atomic models
Early atomic models
The classical planetary model
Let's examine the Hydrogen atom: 1 proton + 1 electron
What is the total energy of the atom
(in the proton's frame)?
Electron's Kinetic Energy
K
=\frac{k e^2}{2r}
Electric Potential Energy
U=k\frac{q_1\ q_2}{r}
=-k\frac{e^2}{r}
=k\frac{e\ (-e)}{r}
Atomic models
Early atomic models
The classical planetary model
Let's examine the Hydrogen atom: 1 proton + 1 electron
What is the total energy of the atom
(in the proton's frame)?
Electron's Kinetic Energy
K
=\frac{k e^2}{2r}
Electric Potential Energy
U=
=-\frac{ke^2}{r}
Total Energy
E=K+U
=\frac{ke^2}{2r}-\frac{ke^2}{r}
=-\frac{ke^2}{2r}
Atomic models
Early atomic models
The classical planetary model
Let's examine the Hydrogen atom: 1 proton + 1 electron
What is the total energy of the atom?
Electron's Kinetic Energy
K
=\frac{k e^2}{2r}
Electric Potential Energy
U=
=-\frac{ke^2}{r}
Total Energy
E
=-\frac{ke^2}{2r}
Atomic models
Bohr's model
Quantization of electronic orbits
Atomic models
Bohr's model
Quantization of electronic orbits
Atomic models
Bohr's model
Quantization of electronic orbits
Bohr's model postulates:
- Only certain "stationary states" exist in atoms.
- In a stationary state, the electron does not radiate energy (as it would classically). The emission and absorption of radiation only occurs in conjunction with a transition between two stationary states.
- These stationary states are determined by a condition imposed on the kinetic energy of the system, or equivalently -for circular orbits- a condition imposed on the electron's orbital angular momentum.
Atomic models
Bohr's model
Quantization of electronic orbits
Atomic models
Bohr's model
Quantization of electronic orbits
r_n=\frac{n^2\hbar^2}{kme^2}=n^2a_0
\text{where} \quad n=1,2,3,...
\text{and} \quad a_0=\frac{\hbar^2}{kme^2}=0.053\text{nm}
E_n=-\frac{k e^2 }{2r_n}=-\frac{1}{n^2}\frac{k e^2 }{2a_0}
=-\frac{13.606\ \text{eV }}{n^2}
\text{where} \quad n=1,2,3,...
Atomic models
Bohr's model
Transitions & atomic spectra
E_n=-\frac{1}{n^2}\frac{k e^2 }{2a_0}
E_i=E_f+E_\gamma
hf=\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)\frac{k e^2 }{2a_0}
The conservation of energy dictates:
substituting
The transition of an atom from a higher-n state to a lower-n state is accompanied by the emission of a bundle of electromagnetic energy (photon):
\implies
E_n=-\frac{1}{n^2}\frac{k e^2 }{2a_0}
E_i+E_\gamma=E_f
hf=\left(\frac{1}{n_i^2}-\frac{1}{n_f^2}\right)\frac{k e^2 }{2a_0}
substituting
The absorption of a bundle of electromagnetic energy (photon) is accompanied by the transition of an atom from a lower-n state to a higher-n state:
\implies
Atomic models
Bohr's model
Transitions & atomic spectra
E_n=-\frac{1}{n^2}\frac{k e^2 }{2a_0}
E_i=E_f+E_\gamma
hf=\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)\frac{k e^2 }{2a_0}
\frac{1}{\lambda}=\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)\frac{k e^2 }{2a_0hc}
\frac{1}{\lambda}=R_H\left(\frac{1}{n^2}-\frac{1}{k^2}\right)
So, to find the emission spectra:
substituting
or, in terms of the wavelength:
Which is identical to the form of the empirical expression
Success!!
Atomic models
Bohr's model
Heavier atoms
For an atom with Z protons
E_n=-\frac{Z^2}{n^2}\frac{k e^2 }{2a_0}
r_n=n^2\frac{a_0}{Z}
and
\text{where} \quad n=1,2,3,...
Atomic models
Bohr's model
Quiz
Name:
n_1=
n_2=
In Bohr's model of the Hydrogen atom, if the atom transitions from the n_1 electronic state to the n_2 state,
a) Does the atom absorb or emit energy?
b) Calculate the wavelength of the emitted/absorbed radiation.
Atomic models
Bohr's model
Quiz
Atomic models
Bohr's model
deBroglie's contribution
Matter waves
Atomic models
Bohr's model
deBroglie's contribution
Matter waves
Atomic models
Bohr's model
deBroglie's contribution
Using deBroglie's matter waves idea, and thinking of the orbiting electron as a standing wave:
2\pi r= n\lambda
2\pi r= n\frac{h}{p}
L=p\ r = n\frac{h}{2\pi}
L=n\hbar
Orbit
circumference
integer number of wavelengths
=
Substitute the deBroglie wavelength of the electron
\lambda=h/p
Recall the definition of the orbital angular momentum
\vec{L}=\vec{p}\times\vec{r}
Atomic models
Bohr's model
Simulator
Atomic models
By omoussa
