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Stokes Friction
Stokes Law
F
drag
=
6
π
μ
R
v
⃗
F_{\text{drag}} = 6 \pi \mu R \vec{\mathbf{v}}
F
drag
=
6
π
μ
R
v
F_{\text{drag}} = 6 \pi \mu R \vec{\mathbf{v}}
Stokes friction
F
Stokes
∝
−
v
⃗
F_{\text{Stokes}} \propto -\vec{\mathbf{v}}
F
Stokes
∝
−
v
F_{\text{Stokes}} \propto -\vec{\mathbf{v}}
Fall with Stokes friction
m
x
¨
=
−
m
g
−
K
x
˙
m\ddot{x} = -mg - K\dot{x}
m
x
¨
=
−
m
g
−
K
x
˙
m\ddot{x} = -mg - K\dot{x}
K
>
0
K > 0
K
>
0
K > 0
1
Resume presentation
Stokes Friction
[Classical Mechanics] Stokes friction
By sebwink
[Classical Mechanics] Stokes friction
a year ago
25
sebwink
PRO
blog.sebwink.net
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