Brine
A certain person trying to make his way in the universe.
Mudstake
5 @ Taiwan IESO Final Selection
Taiwan Impossible Enough Sleep Olympiad
OUtline
Introduction
Basic Information of the Geological Survey
the PUrpose of geo survey
the time of the survey
information of the area
↑source: google
\uparrow \text{source: google}
source: CGS, MOEA→
\text{source: CGS, MOEA} \rightarrow
information of the area
Geological profile→
←source: CGS, MOEA
\leftarrow\text{source: CGS, MOEA}
Xin Yangnyu MUD lake
We were to measure something, I car bon forgot to.
What we've measured
↑source: self
\uparrow \text{source: self}
Where we've measured
↑source: self
\uparrow \text{source: self}
Rough map of the site
↑source: self
\uparrow \text{source: self}
mud cracks
\text{mud cracks}
mud ponds
\text{mud ponds}
bubbles
\text{bubbles}
dry muddy ground
\text{dry muddy ground}
wet muddy ground
\text{wet muddy ground}
Measured data (1)
(ppm)
(ppm)
(s)
(s)
Measured data (2)
(ppm)
(ppm)
(s)
(s)
Measured data (3)
Derivation of fluxes
PV=nRT
PV=nRT
n=RTPV
\displaystyle n=\frac{PV}{RT}
nCO2=RTPCO2V
\displaystyle n_{CO_2}=\frac{P_{CO_2}V}{RT}
Derivation of fluxes
nCO2=RTPCO2V
\displaystyle n_{CO_2}=\frac{P_{CO_2}V}{RT}
dtdnCO2=dtdRTPCO2V
\displaystyle \frac{d}{dt}n_{CO_2}=\frac{d}{dt} \frac{P_{CO_2}V}{RT}
dtdnCO2=RTVdtdPCO2
\displaystyle \frac{d}{dt}n_{CO_2}=\frac{V}{RT} \frac{d}{dt}P_{CO_2}
dtdnCO2=RTPVdtdXCO2
\displaystyle \frac{d}{dt}n_{CO_2}=\frac{PV}{RT} \frac{d}{dt}X_{CO_2}
Derivation of fluxes
dtdnCO2=RTPVdtdXCO2
\displaystyle \frac{d}{dt}n_{CO_2}=\frac{PV}{RT} \frac{d}{dt}X_{CO_2}
Φ=A1dtdnCO2
\displaystyle \Phi = \frac{1}{A}\frac{d}{dt}n_{CO_2}
Φ=ARTPVdtdXCO2
\displaystyle \Phi = \frac{PV}{ART} \frac{d}{dt}X_{CO_2}
Φ=RTPhdtdXCO2
\displaystyle \Phi = \frac{Ph}{RT} \frac{d}{dt}X_{CO_2}
Derivation of fluxes
dtdnCO2=RTPVdtdXCO2
\displaystyle \frac{d}{dt}n_{CO_2}=\frac{PV}{RT} \frac{d}{dt}X_{CO_2}
Φ=A1dtdnCO2
\displaystyle \Phi = \frac{1}{A}\frac{d}{dt}n_{CO_2}
Φ=ARTPVdtdXCO2
\displaystyle \Phi = \frac{PV}{ART} \frac{d}{dt}X_{CO_2}
Φ=RTPhdtdXCO2
\displaystyle \Phi = \frac{Ph}{RT} \frac{d}{dt}X_{CO_2}
}
\Biggl\}
}
\}
9 cm
9\ cm
1 cm
1\ cm
Results
Φ(mol/m2s)=R(J/K⋅mol)T(K)P(N/m2)⋅h(m)dtdXCO2(1/s)
\Phi(mol / m^2s) = \frac{P(N/m^2)\cdot h(m)}{R(J / K \cdot mol)T(K)} \frac{d}{dt}X_{CO_2}(1/s)
total amount of gas
↑source: self
\uparrow \text{source: self}
mud cracks
\text{mud cracks}
mud ponds
\text{mud ponds}
bubbles
\text{bubbles}
dry muddy ground
\text{dry muddy ground}
wet muddy ground
\text{wet muddy ground}
total amount of gas
Effect on global warming
My Questions
What I started to ponder.
How much carbon are there?
←source: USGS
\leftarrow\text{source: USGS}
For how long exactly
Conclusion
Reflection from the geological survey
Measured data
Future WOrks
References
- Laura Cozzi et al. (2023), The world’s top 1% of emitters produce over 1000 times more CO2 than the bottom 1%. https://www.iea.org/commentaries/the-world-s-top-1-of-emitters-produce-over-1000-times-more-co2-than-the-bottom-1
- 林啟文(2013). Chishan [Geological map of Taiwan 1/50,000]. CGS, MOEA.
Thank you
Questions are welcomed, I will not resist.
Mudstake 5 @ Taiwan IESO Final Selection Taiwan Impossible Enough Sleep Olympiad
5-期末口頭報告
By Brine
5-期末口頭報告
A mudstake made by Caldera 5
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